Answer:
Maximum : 51
Minimum: 12
Median: 38
Lower quartile: 19
Upper quartile: 46
Step-by-step explanation:
To answer this question, we first order the data from largest to smallest:
46, 19, 38, 27, 12, 38, 51
12, 19, 27, 38, 38, 46, 51
It can be seen that the maximum value is:
51
The minimum value is
12
Let's call N the amount of data.
To calculate the quartiles we use the following formula:

So:


Where
is the data number 2.
Q1 = 19
As the number of data is imapar, then, the median is the central data:
12, 19, 27, {38}, 38, 46, 51
Median = 38
Finally:

Where
represents the data number 6
