The LCM is 24.
1/12=2/24
5/8=15/24
The simplified expression of 32/5 x 3(-7/5) is -672/25
<h3>How to simplify the expression?</h3>
The mathematical expression is given as:
32/5 x 3(-7/5)
Evaluate the product of 3 and -7/5
32/5 x 3(-7/5) = 32/5 x -21/5
Evaluate the product of 32 and -21
32/5 x 3(-7/5) = 672/5 x -1/5
Evaluate the product of 5 and 5
32/5 x 3(-7/5) = 672/25 x -1
So, we have:
32/5 x 3(-7/5) = -672/25
Hence, the simplified expression of 32/5 x 3(-7/5) is -672/25
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D. f(x+1)=2f(x)
f(x+1)=2(-2 2/3)=-5 1/3
f(x+1)=2(-5 1/3)=-10 2/3
f(x+1)=2(-10 2/3)=-21 1/3
f(x+1)=2(-21 1/3)=-42 2/3
It depends, not exactly, because the techtonic plates aren't connected.
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height