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coldgirl [10]
3 years ago
5

Find the volume of the given solid​

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

15,000cm^3

Step-by-step explanation:

Dividing the solid into 2;

Volume = Volume of A + Volume of B

Volume of Top prism (A) =25cm * 20cm * 10cm

Volume of Top prism (A) = 5000cm^3

Volume of bottom prism B = 20cm * 50 * 10

Volume of bottom prism B = = 10000cm^3

Volume of the figure = 5000 + 10000

Volume of the figure = 15,000cm^3

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In a book of stickers the ratio of large stickers to small stickers is 7 to 5. Based on this ratio, how many large stickers are
Archy [21]
Large sticker : Small sticker = 7 : 5

Find total parts:
7 + 5 = 12  

Find 1 part:
12 parts = 96 stickers
1 part = 96 ÷ 12 = 8 stickers

Find 7 parts:
1 part = 8 stickers
7 parts = 7 x 8 = 56 stickers

Answer: There are 56 large stickers
7 0
3 years ago
3 QUESTIONS-30 POINTS<br> ATTACHMENTS BELOW
yan [13]

(6) 70, 70, 110

∠2 = ∠4 = 110° ( congruent angles )

∠3 = 180° - 110° = 70° ( straight angle )

∠1 = 70° ( vertically opposite ∠3 )

(9) ∠AEC = 15x - 11

since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1

∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11

(7) x = 3

AC = AB + ABC = 32

2x + 6x + 8 = 32

8x + 8 = 32 ( subtract 8 from both sides )

8x = 24 ( divide both sides by 8 )

x = 3



3 0
4 years ago
Very easy question please help I cant do basic math ​
Tom [10]
Sonic sick duck duck
3 0
3 years ago
What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300
hodyreva [135]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30

It can be written as

2(\ln 2x)-(\ln 10x)=\ln 30         [\because \ln e^a=a]

\ln (2x)^2-(\ln 10x)=\ln 30        [\because \ln a^b=b\ln a]

\ln \dfrac{4x^2}{10x}=\ln 30        [\because \ln \dfrac{a}{b}=\ln a-\ln b]

\ln \dfrac{2x}{5}=\ln 30

On comparing both sides, we get

\dfrac{2x}{5}=30

Multiply both sides by 5.

2x=150

Divide both sides by 2.

x=75

Therefore, the correct option is B.

7 0
4 years ago
Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y
castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Fail the test.
  • Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

  • 46% of 37%(are fit).
  • 100% of 63%(not fit).

Hence:

P(A) = 0.46(0.37) + 0.63 = 0.8002

The probability of both failing the test and being unfit is:

P(A \cap B) = 0.63

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0
3 years ago
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