Answer:
A) (-5, -34)
Step-by-step explanation:
f(x) = x^2 + 10x - 9
We complete the square to get the equation in vertex form
Take the coefficient of the x term and divide by 2 then square it. We add it and then subtract it not to change the value of the equation
f(x) = x^2 + 10x +(10/2)^2 - (10/2)^2 - 9
f(x) = x^2 +10x +25 -25 -9
f(x) = (x^2 +10x +25) -34
The term in parentheses simplified to (x+10/2) ^2
= (x+5)^2 -34
= (x - -5)^2 -34
This is in the form (x-h)^2 +k
The vertex is (h,k) h=-5 and k=-34
(-5,-34)
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
Answer:
B
Step-by-step explanation:
So we have the formula:
And we want to solve it for r.
So, let's first divide both sides by π and h. This will cancel out the right side:
Now, take the square root of both sides:
And we're done!
Our answer is B.
I hope this helps!
That's the simplest it can go.
Answer:
in polynomial form
Step-by-step explanation:
if you have any question then reply me
