Question

Given KW is perpendicular to JO, JP is perpendicular to KO, KN intersects with JP=Q. Prove that triangle OKW ~ triangle OJP

Answer 1

Answer:

Proved

Step-by-step explanation:

m∠JPO  = 90  =  m∠OWK, and angle O is common between both triangles [reflexive property]. Therefore by Rule AA, ΔOKW~ΔOJP