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2 years ago

Me when i was little i looked so weird

Mathematics

2 answers:

Lyrx [107]2 years ago

7 0

Answer:

Ok...

Step-by-step explanation:

givi [52]2 years ago

4 0

Once upon a time, there was a lovely princess. But she had an enchantment upon her of a fearful sort, which could only be broken by love's first kiss. She was locked away in a castle, guarded by a terrible fire-breathing dragon. Many brave knights had attempted to free her from the dreadful prison, but none prevailed. She waited in the dragon's keep, in the highest room of the tallest tower, for her true love and true love's first kiss." [Laughing] Like that's ever gonna happen.
[Paper Rustling, Toilet Flushes]
Shrek: What a load of--

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Which best describes the range of numbers that satisfy the inequality x> 124?

nekit [7.7K]

Answer:

Answer shown below

Step-by-step explanation:

The range has a lower limit but no upper band limit

(124, infinity)

4 0

3 years ago

What is the value of x?

Mrrafil [7]

Answer:

Step-by-step explanation:

Triangles with the same shape but different size are proportional. Proportional means that their side lengths form equal ratios. To solve for x, set up a proportion.

The ratios we will create will be $\frac{long}{short} =\frac{long}{short}$ where each long and short are corresponding sides from each triangle.

So write:

$\frac{4}{x} =\frac{3}{2.25}$

To solve, cross multiply numerator with denominator.

4(2.25) = 3(x)

9 = 3x

3 =x

5 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$