We will see that the solution in the given interval is: x = 0.349 radians.
<h3>How to solve equations with the variable in the argument of a cosine?</h3>
We want to solve:
cos(3*x) = 1/2
Here we must use the inverse cosine function, Acos(x). Remember that:
cos(Acos(x)) = Acos(cos(x)) = x.
If we apply that in both sides, we get:
Acos( cos(3x) ) = Acos(1/2)
3*x = Acos(1/2)
x = Acos(1/2)/3 = 0.349
So x is equal to 0.349 radians, which belongs to the given interval.
If you want to learn more about trigonometry, you can read:
brainly.com/question/8120556
Answer:
10
Step-by-step explanation:
Area= 3.14 x 6squared
= 113.04m
Answer:
independent
Step-by-step explanation:
Since no one else answered, figured you wouldn't mind if I do. :-), and you didn't use any CAPS.
How those two events (even and greater than 9) relate?
independent: YES. Can one happen without the other? Certainly. You see (1,1) is an even number that is not greater than 9. Equally, you see (6,5) which is greater than 9, but is not an even number.
inclusive: No, since there's a least one case where a pair number is not greater than 9. The opposite is also true... at least 1 number > 9 that is not even.
Mutually exclusive: No, since there numbers that are even AND greater than 9 (6,4) for example.
Conditional: No. Does one need the other to happen? Absolutely not.
