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2 years ago

11

Angle

1 answer:

prisoha [69]2 years ago

4 0

Answer:

hope this helps

Step-by-step explanation:

Angle _1_and angle _4_ are vertical angle pairs.

Angle _4_ and angle _5_ are an alternate interior pair.

Angle _2_ and angle _6_ are alternate exterior pair.

Angle _1_ and angle _2_ are a linear angle pair.

Angle _2_ and angle _7_ are corresponding angle pair.

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A bike rider is traveling at a speed of 15 feet per second. Write an expression for the distance the rider has traveled after s

bija089 [108]

distance = speed x time

distance time

45 ft 3.0 s

87 ft 5.8 s

166.5 ft 11.1 s

210 ft 14.0 s

4 0

2 years ago

Each team in the softball league plays each of the other teams exactly once. If

Aleks04 [339]

<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
t^2 -t -42=0
(t-7)(t+6)
t=7 ; t=-6

Excluding the minus result, you got 7 teams.

6 0

3 years ago

Find the values for c and d

baherus [9]

Answer:

c=-5

d=1

Step-by-step explanation:

$(cy^2)(4y^d)=-20y^3$

I'm going to reorder the left-hand side. Multiplication is commutative.

$(4c)(y^2y^d)=-20y^3$

Since the bases are the same in $y^2y^d$ and the operation is multiplication, I'm going to add the exponents giving me:

$4cy^{2+d}=-20y^3$

So this implies we have two equations to solve:

$4c=-20$ and $2+d=3$

So the first equation can be solved by dividing both sides by 4 giving you $c=-5$ .

The second equation can be solved by subtracting 2 on both sides giving you $d=1$ .

6 0

3 years ago

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log2, então o valor de é

sveticcg [70]

Answer:

$\frac{x}{y}=1.3$

Step-by-step explanation:

<u>Informação recuperada:</u>

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é

1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:

$10x=20y \Rightarrow x=log_{10}20y$

2) Aplicando a propriedade do produto de logaritmo:

$log(AB)= logA+logB$

$x=log_{10}20y \Rightarrow x=log(2+10)y\Rightarrow x=(0.3+1)y \Rightarrow x=1.3y$

3) Como quero o quociente divido ambos os lados por y

$\frac{x}{y}=\frac{1.3y}{y}\Rightarrow \frac{x}{y}=1.3$

4 0

2 years ago

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago