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sveticcg [70]
3 years ago
5

Please help if you can

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Option D

Step-by-step explanation:

Formula to be used,

Scale factor = \frac{\text{Dimension of the image rectangle}}{\text{Dimension of the original}}

By this formula,

\frac{7}{2}=\frac{\text{Length of the dilated rectangle}}{\text{Length of the original rectangle}}

\frac{7}{2}=\frac{L}{22}

L = \frac{7\times 22}{2}

  = 77 inches

Similarly, width of the the dilated rectangle = \frac{7}{2}\times 10

                                                                        = 35 inches

Perimeter of the new rectangle = 2(Length + width)

                                                    = 2(77 + 35)

                                                    = 224 inches

Option (D) will be the correct option.

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\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\  both\  sides\  of\  the\  equation\ (2)\   by\  y\  (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\  substitute\  equation\  (1)\  into\  equation\  (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\  both\  sides\  of\  the \ equation\  by\  4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

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