Question

The Ferris wheel has a radius of 70 feet. The distance between the wheel and the ground is 4 feet. The rectangular coordinate system shown has its origin on the ground directly below the center of the wheel. Write the equation of the circular wheel. (JUSTIFY)
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Answer 1

Answer:

The equation of the circular wheel is $x^2+(y-74)^2=(70)^2$.

Step-by-step explanation:

Given :

Radius of Ferris wheel r = 70 feet.

The distance between the wheel and the ground = 4 feet.

Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.

So the x coordinate of center of wheel must  be 0 , and y coordinate = 70 + 4 = 74

Thus, Coordinates of center = (0,74)

The equation of circle is given by :-

$(x-h)^2+(y-k)^2=r^2$

Now center (h,k) = (0,74) and r = 70 , we get

$x^2+(y-74)^2=(70)^2$

Hence, the equation of the circular wheel is $x^2+(y-74)^2=(70)^2$.