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AURORKA [14]
3 years ago
6

Work out x² -11x+18=0

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer: x=2 or x=9

Step-by-step explanation:

Step 1: Factor left side of equation.

(x−2)(x−9)=0

Step 2: Set factors equal to 0.

x−2=0 or x−9=0

x=2 or x=9

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Evaluate the expression 120n + 160 then n=5
Mamont248 [21]

Answer:

760

Step-by-step explanation:

First you multiply 120 by 5 because n equals five which equals 600 then add 160 which equals 760

5 0
3 years ago
Read 2 more answers
Enter the value of P so that the expression 3 (4 + n) is equivalent to 3 (n+p).
Gala2k [10]

Answer:

3 (4+n)=0

3×4+3×n=0

12+3n=0.... equation 1

3 (n+p)

3×n+3×p=0

3n+3p=0........... equation 2

eq 1 multiply 3 eq 2 multiply 3

36+9n=0

9n+9p=0

_ _ =0

_9n is +9n Crush

36+9p=0

p=36÷9

p=4

p is 4 ans

4 0
3 years ago
Is (5,50) a solution to the linear system y = 5x + 25 and y = 3x + 35? Explain your reasoning.
IRINA_888 [86]

Answer:  Yes (5, 50) is a solution

========================================================

Explanation:

The point (5, 50) means x = 5 and y = 50 pair up together.

Plug those values into the first equation and simplify both sides as much as possible. This is so we have one number on each side.

y = 5x+25

50 = 5*5+25

50 = 25+25

50 = 50

Because we ended up with a true statement at the end, this makes the original equation y = 5x+25 to be true when (x,y) = (5,50).

In other words, the first equation has been confirmed.

---------

Repeat those steps for the second equation

y = 3x+35

50 = 3*5+35

50 = 15+35

50 = 50

We get another true statement, and we've confirmed the second equation.

Both equations are true when (x,y) = (5, 50)

---------

This fully confirms that (5, 50) is indeed a solution to this system.

It turns out it's the only solution. Visually we can verify this by looking at the graph. The two lines intersect at one location and it is (5, 50).

See below.

5 0
2 years ago
Skylar is going to invest $69,000 and leave it in an account for 6 years. Assuming the
SSSSS [86.1K]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$105000\\ P=\textit{original amount deposited}\dotfill & \$69000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &6 \end{cases}

105000=69000e^{\frac{r}{100}\cdot 6}\implies \cfrac{105000}{69000}=e^{\frac{3r}{50}}\implies \cfrac{7}{46}=e^{\frac{3r}{50}} \\\\\\ \log_e\left( \cfrac{35}{23} \right)=\log_e\left( e^{\frac{3r}{50}} \right)\implies \ln\left( \cfrac{35}{23} \right)=\cfrac{3r}{50}\implies 50\cdot \ln\left( \cfrac{35}{23} \right)=3r \\\\\\ \cfrac{50\cdot \ln\left( \frac{35}{23} \right)}{3}=r\implies 6.9976\approx r\implies \stackrel{\%}{7.00}\approx r

8 0
3 years ago
Find the area of the following parallelogram
laila [671]

Answer:

6 cm^2

Step-by-step explanation:

The area of a parallelogram is

A = bh where b is the base and h is the height

A = 3 *2 = 6 cm^2

6 0
4 years ago
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