Answer:
<em>In 5 years the product of their ages will be 208</em>
Step-by-step explanation:
The age of two children is 11 and 8 years.
Let's call x the number of years ahead.
We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:
(11+x)(8+x)=208
Operating:
![88+11x+8x+x^2=208](https://tex.z-dn.net/?f=88%2B11x%2B8x%2Bx%5E2%3D208)
Simplifying:
![x^2+19x-120=0](https://tex.z-dn.net/?f=x%5E2%2B19x-120%3D0)
Factoring:
(x-5)(x+24)=0
Solving:
x=5, x=-24
The negative solution is not valid, thus x=5
In 5 years the product of their ages will be 208
2x(-5x-3)
2x(-5x)= -10x and 2x(-3)= -6x
= -10x sq - 6x
-10x is sq bc you are multiplying the same variable twice
Answers:
2x - 6y = 8 -> x = 4 + 3y
-3x + 9y = 12 -> x = -4 + 3y
Answer:
ALL CAN BE MADE IN SOLID FIGURES