Help me please!<br> If you get it right, I’ll will brainliest u!!

Probability and Two-Way Tables

alisha [4.7K]

A and X are two independent events , Option A is the correct answer.

<h3>When is Probability ?</h3>

Probability is the likelihood of an event to happen

A two way table is given

The two events will be independent when

If A is the first event and B is the second event , then

P(A) = P(A|B)

Here the P(A) = 30/100 = 0.3

P(B) = 20/100 = 0.2

P(A|X) = 15/50 = 0.3

P(A) = P(A|X)

Therefore A and X are two independent events , Option A is the correct answer.

To know more about Probability

brainly.com/question/11234923

#SPJ1

5 0

1 year ago

Read 2 more answers

9,003,809,123 in word form

aivan3 [116]

ooh well this will be fun

nine billion three million eight hundred thousand nine one hundred and twenty three

please subscribe to me on yt to help me out im a newbie and subing will mean the world to me h t t p s : / / w w w . y o u t u b e . c o m / c h a n n e l / U C F H b 0 O V W J P q p a N a M m u 3 k I L w

5 0

2 years ago

Read 2 more answers

Find the area of the shape shown below.

valkas [14]

Answer:

<h2><em><u>12 is the total area</u></em></h2>

Step-by-step explanation:

A of triangle = 1/2 * b * h

b = 6

h = 2

2 * 6 * 0.5

= 12 * 0.5

A of square = l * w

2 * 2

A of Triangle = 1/2 * b * h

2 * 2 * 0.5 =

4 * 0.5

2 + 4 + 6

= 6 + 6

6 0

2 years ago

Rupali has a piece of string that is 5/8 hard long. She wants to cut the string into 4 equal pieces. How long should each piece

AlexFokin [52]

The answer would be 1/7 in fraction form , and 0.142857 in decimal form. hope this helps!

4 0

3 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Help me please! If you get it right, I’ll will brainliest u!!