Answer:
C. z = 2.05
Step-by-step explanation:
We have to calculate the test statistic for a test for the diference between proportions.
The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

The difference between proportions is (p1-p2)=0.0219.
 
The pooled proportion, needed to calculate the standard error, is:

The estimated standard error of the difference between means is computed using the formula:

Then, we can calculate the z-statistic as:

z=2.05
 
        
             
        
        
        
<span>1.       </span><span>Given equation = 2 thousands 7
tens / 10.
From this given equation, give the unit form and the standard form
Unit form is the expression where you replace the number with its place values.
=> 2 thousands and 7 tens divided by 1 tens.
=> 2 hundreds 7 ones – answer in unit form
Standard form is the expression which uses numbers and operators to express an
equation.
=> 2 070 / 10
=> 207 – answer in standard form</span>
        
                    
             
        
        
        

We know that,
- Pythagoras theoram is given by : p² + b² = h²
- In a Pythagoras triplet, the longest side represents the hypotenuse of the triangle.
Then,
We should check that, whether the sum of squares of the smaller sides will be equal to the square of the third side or not. Then, we can determine the above easily.
Sum of squares of smaller sides:
= 6² + 8²
= 36 + 64 
= 100
Square of longer side:
= 10²
= 100
Sum of squares of smaller sides = Square of longer side. Hence, 6,8,10 are Pythagorean triplets. 
And we are done! :D
⛱️ 
 
        
             
        
        
        
Answer:
35.25
Step-by-step explanation:
Give the data set: 
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of 
 22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of 
 37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
 
        
             
        
        
        
Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 =   (x/3)*x - 2   =  (x^2)/3 - 2     (*)
1 \3x - 4   =  (1/3)x - 4                               (**)
(*) = (**)   =>
(x^2)/3 -2 = (1/3)x - 4        => multiply both sides by 3
x^2 - 6 = x - 12                 => subtract x from both sides
x^2 -x -6 = -12                   => add 12 to both sides
x^2-x +6  = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB