Barney has 1 16

In the metric system, multiplying by 1000 would be the same as moving the decimal point _____ place(s) to the right.

hodyreva [135]

It would be the same as moving the decimal three to the right, and that applies to everything, not just the metric system.

3 0

3 years ago

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The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0

3 years ago

I NEED THE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 1/7-3(3/7x-2/7)

melomori [17]

Step-by-step explanation:

x in (-oo:+oo)

1/7-(3*((3/7)*x-(2/7))) = 0

1/7-3*((3/7)*x-2/7) = 0

1/7-3*(3/7*x-2/7) = 0

(-3*7*(3/7*x-2/7))/7+1/7 = 0

1-3*7*(3/7*x-2/7) = 0

7-9*x = 0

(7-9*x)/7 = 0

(7-9*x)/7 = 0 // * 7

7-9*x = 0

7-9*x = 0 // - 7

-9*x = -7 // : -9

x = -7/(-9)

x = 7/9

6 0

3 years ago

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Complete parts (a) through (c) below.

Yuki888 [10]

Answer:

a) $t_{crit}= 1.34$

b) $t_{crit}=-2.539$

c) $t_{crit}=\pm 2.228$

Step-by-step explanation:

Part a

The significance level given is $\alpha=0.1$ and the degrees of freedom are given by:

$df = n-1= 15$

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

$t_{crit}= 1.34$

Part b

The significance level given is $\alpha=0.01$ and the degrees of freedom are given by:

$df = n-1= 20-1=19$

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

$t_{crit}=-2.539$

Part c

The significance level given is $\alpha=0.05$ and $\alpha/2 =0.025$ and the degrees of freedom are given by:

$df = n-1= 11-1=10$

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

$t_{crit}=\pm 2.228$

4 0

3 years ago

Adam drove 280 miles in 4 hours. On average, how fast did he drive in hours per mile? Express your answer in simplest form.

Natasha2012 [34]

Answer:

1/70 hours per mile

Step-by-step explanation:

We want hours per mile

Take the hours and divide by the miles

4 hours / 280 miles

1 hours/ 70 miles

7 0

3 years ago

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