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2 years ago

Answer please ASAP :))))

Mathematics

2 answers:

vazorg [7]2 years ago

8 0

Answer:

0.056, 0.060, 0.560, 0.600, 6.00

Step-by-step explanation:

Place Value Chart

Tens ---- Ones --- Tenths ---- Hundredths ---- Thousandths

(think about where the values go in the chart)

azamat2 years ago

3 0

Answer:

good luck with maths! i know it can be tricky

Step-by-step explanation:

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Anyone by chance know how to answer this geometry question I need help so bad

NemiM [27]

Answer:

x = -8 and BDC is 68 degrees.

Step-by-step explanation:

Combine -7x+12 and -8x+48 to get -15x+60. Since BDA is a straight angle put the above equation to get -15x+60=180. Subtract 60 from both sides to get -15x=120. Divide -15 both sides to get -8 as your x value. Plug in -8 to BDC, since both negatives are being multiplied, it would turn to a positive number which is 56, add 12 to get 68 as your final result for BDC.

8 0

3 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

Please assist me with these problems

Vinil7 [7]

Part (a)

<h3>Answer: y1 and y3 are perpendicular</h3>

This is because the two slopes 2 and -1/2 multiply to -1. Perpendicular slopes multiply to -1 assuming neither line is vertical or horizontal.

=====================================================

Part (b)

Graph each line to see where they cross. The three points of intersection are

(0,4)

(2,-2)

(4,2)

The order of the points doesn't matter.

You could also form three systems of equations pairing up the equations, and solving each system. That way you can find the points of intersection. Graphing may be a better and faster route in my opinion. See the diagram below.