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3 years ago

Help please!-

Physics

1 answer:

BigorU [14]3 years ago

8 0

Answer:

Current = 2 Amperes

Explanation:

Given the following data;

Resistance = 8 Ohms

Power = 32 W

To find the amount of current going through the speaker;

Mathematically, power can be calculated using the formula;

Power = current² * resistance

Substituting into the formula, we have;

32 = current² * 8

Current² = 32/8

Current² = 4

Taking the square root of both sides, we have;

Current = √4

Current = 2 Amperes

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A ball is thrown vertically upward with a speed of 27.9 m/s from a height of 2.0 m. How long does it take to reach its highest p

Bas_tet [7]

Answer:

2.84403 seconds

2.91483 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-27.9}{-9.81}\\\Rightarrow t=2.84403\ s$

It takes 2.84403 seconds to reach the highest point

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-27.9^2}{2\times -9.81}\\\Rightarrow s=39.67431 m$

The ball will travel 39.67431+2 = 41.67431 m while going down to the ground

$s=ut+\frac{1}{2}at^2\\\Rightarrow 41.71479=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{41.67431\times 2}{9.81}}\\\Rightarrow t=2.91483\ s$

The ball takes 2.91483 seconds to hit the ground after it reaches its highest point.

6 0

3 years ago

What is the density at 20oC of 12.0 milliliters of a liquid that has a mass of 4.05 grams?0.338 g/mL

Ilya [14]

Answer: A. 0.338 g/ml

Explain:
D = m/V = 4.05/12 = 0.3375 = 0.338 g/mL

3 0

3 years ago

Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a ______________ .

Anna35 [415]

Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a __suspension__ .

7 0

4 years ago

Read 2 more answers

Steam at 400C has a specific volume of 0.02m3/kg. Determine the pressure of the steam based on a) the ideal gas equation b) the

nikklg [1K]

Answer:

by ideal gas pressure = 15529.475 kPa

by compressibility chart pressure = 12576 kPa

by steam tables Pressure = 12517 kPa

Explanation:

given data

temperature T = 400°C = 673 K

volume v = 0.02 m³/kg

to find out

pressure by ideal gas, compressibility chart and steam tables

solution

we know here by table

gas constant R is 0.4615 kJ/ kg-K

and critical temp Tc = 647.1 K

and critical pressure Pc = 22064 kPa

so by ideal gas pressure is

pressure = R×T / v

pressure = 0.4615 × 673 / 0.02

pressure = 15529.475 kPa

and

by compressibility chart

temperature reduce is = T/ Tc

temperature reduce Tr = 673 / 647.1

Tr = 1.040 K

so pseudo reduce volume is here

reduce volume Vr = v / ( RTc/Pc)

reduce volume Vr = $\frac{0.02}{\frac{461.5(647.1)}{22064*10^{3} } }$

0.02 / ( 461.5(647.1) / 22064×10³)

reduce volume = 1.48

and we know by compressibility chart

reduce pressure Pr is 0.57

pressure = Pr × Pc

pressure = 0.57 × 22064 × 10³

pressure = 12576 kPa

and

from steam table

pressure is 12.5 MPa at 673 K and 0.020030 m³/kg

pressure is 15 MPa at 673 K and 0.015671 m³/kg

pressure P is

$\frac{0.02 - 0.020030}{0.015671 - 0.020030}$ = $\frac{ P - 12.5}{15 - 12.5}$

Pressure = 12517 kPa

4 0

3 years ago

A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some ins

Delvig [45]

Answer:

$B= 1.14 X 10^{-7} Tesla$

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

$B=\frac{I\mu}{2r\pi}$

$B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}$

$B= 1.14 X 10^{-7} Tesla$

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

6 0

3 years ago