Answer:
The initial velocity is 50 m/s.
(C) is correct option.
Explanation:
Given that,
Time = 10 sec
For first half,
We need to calculate the height
Using equation of motion
![v^2=u^2+2gh](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2gh)
....(I)
For second half,
We need to calculate the time
Using equation of motion
![h =ut+\dfrac{1}{2}gt_{2}^2](https://tex.z-dn.net/?f=h%20%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dgt_%7B2%7D%5E2)
![h=0+\dfrac{1}{2}gt_{2}^2](https://tex.z-dn.net/?f=h%3D0%2B%5Cdfrac%7B1%7D%7B2%7Dgt_%7B2%7D%5E2)
![t_{2}=\sqrt{\dfrac{2h}{g}}](https://tex.z-dn.net/?f=t_%7B2%7D%3D%5Csqrt%7B%5Cdfrac%7B2h%7D%7Bg%7D%7D)
Put the value of h from equation (I)
![t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}](https://tex.z-dn.net/?f=t_%7B2%7D%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%20v%5E2%7D%7Bg%5E2%7D%7D)
![t_{2}=\dfrac{v}{g}](https://tex.z-dn.net/?f=t_%7B2%7D%3D%5Cdfrac%7Bv%7D%7Bg%7D)
According to question,
![t_{1}+t_{2}=10](https://tex.z-dn.net/?f=t_%7B1%7D%2Bt_%7B2%7D%3D10)
![t_{1}=t_{2}](https://tex.z-dn.net/?f=t_%7B1%7D%3Dt_%7B2%7D)
Put the value of t₁ and t₂
![\dfrac{v}{g}+\dfrac{v}{g}=10](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%7D%7Bg%7D%2B%5Cdfrac%7Bv%7D%7Bg%7D%3D10)
![\dfrac{2v}{g}=10](https://tex.z-dn.net/?f=%5Cdfrac%7B2v%7D%7Bg%7D%3D10)
![v=\dfrac{10\times g}{2}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B10%5Ctimes%20g%7D%7B2%7D)
Here, g = 10
The initial velocity is
![v=\dfrac{10\times10}{2}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B10%5Ctimes10%7D%7B2%7D)
![v=50\ m/s](https://tex.z-dn.net/?f=v%3D50%5C%20m%2Fs)
Hence, The initial velocity is 50 m/s.
They all have a special way in their age how they want to get taught things but there abilities make them special
If it is eight meters per second, and the total distance he has to travel is four hundred meters to complete the race, you divide the total length needed to travel by the average speed per second to see the amount of seconds required to complete the race at that speed.
8 meters per second: Speed of runner
400 meters: Total distance
400/8=50
50 seconds to complete the race at the eight of 8m/s.
Ticker Tape analysis is a common way of analyzing the motion of the objects to perform in the physics laboratory. A long tape is attached to a moving object and threaded through a device that places a tick upon the tape at regular intervals of time. This ticker tape can also determine if the object is fast or slow. It can also reveal if the object is moving with a constant velocity or accelerating. The changing velocity and acceleration represented by the changing distance between dots in the ticker tape. And also the constant velocity and therefore no acceleration represent the constant distance between dots.