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frosja888 [35]
3 years ago
14

Complete the sentence. (889x27)+50 is than 889x27

Mathematics
2 answers:
Rashid [163]3 years ago
8 0

Answer: 889 x 27 + 50 is greater than 889 x 27.

Step-by-step explanation: Hope this helps

k0ka [10]3 years ago
8 0

Answer:

greater than

Step-by-step explanation:

(889x27)+50 is greater than 889x27

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Which statement is true?
defon

Answer:

b. Multiplying decimals less than one is finding a part of a part.

Step-by-step explanation:

A part of a given number implies a selected part of a given number which can be expressed as a fraction of the number. Example, the half of any number is \frac{1}{2}.

The product of a part and another part can be expressed as;

\frac{1}{3} x \frac{2}{3} = \frac{2}{9}

or,

\frac{1}{2} x \frac{1}{2} = \frac{1}{4}

or,

\frac{1}{2} x \frac{2}{3} = \frac{2}{6} = \frac{1}{3}

The three examples shows: a part x a part.

Therefore, it would be observed that multiplying decimals less than one is the same as finding a part of a part.

5 0
3 years ago
A lawn mower manufacturer incurs a total of $34,816 in overhead costs and $388 per lawn mower in production costs. How many lawn
blsea [12.9K]
Let x represent the amount of lawn mowers that were manufactured

The company has to pay $34,816 before they even make any lawn mowers plus $388 per lawn mower.

((34816+388x)/x)=660
34816+388x=660x
34816=272x
X=128

Therefore, there were 128 lawn mowers manufactured
5 0
4 years ago
Factor -8c^5d^6-27c^4d^4-24c^2d^3
Nikolay [14]
GCF  =   -c^2d^3

Factors are  -c^2d^3(8c^3d^3 + 27c^2d + 24)
7 0
3 years ago
What is the ratio for 8 and 12
Vitek1552 [10]
It can be 8:12 or as a fraction it’s 8/12
5 0
3 years ago
HELP ME PLZ WILL MARK BR ASAP
Murljashka [212]

Answer:

the answer is A. 47

Step-by-step explanation:

tanθ = 15/14

the answer for 15/14 comes out to be about 1.0714 and so you put that value into your calculator using the sin^-1 button. it should look something like this sin^-1(1.0714) and press enter and you'll get 46.974 and round will result in 47

3 0
3 years ago
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