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kozerog [31]
2 years ago
10

Rectangle measures 10 inches by 5 inches. Rectangle B is a scaled copy of Rectangle Select all of the measurement pairs that cou

ld be the dimensions of Rectangle B.
I NEED HELP PLZZZ
Mathematics
1 answer:
Reika [66]2 years ago
4 0

Answer:

I would help but the thing is there is no options so sorry man

Step-by-step explanation:

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Convert 18532.6 into scientific notation
balandron [24]
Here's what you need to do:

Well, you can't there's no zeros so this will be the answer

18532.6×10^0=

That would be your answer.
7 0
3 years ago
If s ( x ) = 2 - x² and t ( x ) = 3x, what is s ( t ( -7 ) )?
soldi70 [24.7K]

Answer:

- 439

Step-by-step explanation:

  • s ( x ) = 2 - x²
  • t ( x ) = 3x
  • s ( t ( -7 ) ) = ?

--------------------------

  • t (-7) = 3 * ( -7 ) = -21
  • s ( t ( -7 ) ) = s ( -21 ) = 2 - ( -21 )² = 2 - 441 = - 439
  • s ( t ( -7 ) ) = -439
5 0
2 years ago
What is the zeros of the quadratic function y=x^2+14x+24
777dan777 [17]

Step-by-step explanation:

{x}^{2}  + 14x + 24 = 0 \\  {x}^{2}  + 12x + 2x + 24 = 0 \\ x(x + 12) + 2(x + 12) = 0 \\ (x + 12)(x + 2)  = 0\\ x =  - 12 \\ x =  - 2

6 0
3 years ago
during a sale at the bookstore,books where sold for $3 and magazines where sold for $2.50 Jam spent $16 and bought a total of 6
VashaNatasha [74]
The bookstore is on sale and they offer the following prices to the following items:  => books is equals to 3 dollars => magazines  costs 2.50 dollars.Now, Jam were able to spend 16 dollars in total in buying 6 books and x number of magazines. => Let's find out how many did Jam bought. => he bought a total of 6 books and magazine.=> Let's analyze how many magazines and how many books will he need to buy in order to get 16 dollars in total=> 4 magazines * 2.5 dollars = 10 dollars=> 2 books * 3 dollars = 6 dollarsin total 16 dollars.<span>
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7 0
3 years ago
A+b=180<br> A=-2x+115<br> B=-6x+169<br> What is the value of B?
natulia [17]
The answer is:  " 91 " .   
___________________________________________________
                    →    " B = 91 " .
__________________________________________________ 

Explanation:
__________________________________________________
Given:  
__________________________________________________
    "  A +  B = 180 " ;

  "A =  -2x + 115 " ;   ↔  A =  115 − 2x ;  

  "B = - 6x + 169 " ;  ↔  B = 169 − 6x ;  
_____________________________________________________
METHOD 1)
_____________________________________________________
Solve for "x" ; and then plug the solved value for "x" into the expression given for "B" ; to  solve for "B"
_____________________________________________________

(115 − 2x) + (169 − 6x) = 

  115 − 2x + 169 − 6x = ?

→ Combine the "like terms" ;  as follows:

      + 115 + 169 = + 284 ; 

 − 2x − 6x = − 8x ; 
_________________________________________________________
And rewrite as:

 " − 8x + 284 " ; 
_________________________________________________________
   →  " - 8x + 284 = 180 " ; 

Subtract:  "284" from each side of the equation:

  →  "  - 8x + 284 − 284 = 180 − 284 " ; 

to get:

 →  " -8x = -104 ; 

Divide EACH SIDE of the equation by "-8 " ; 
    to isolate "x" on one side of the equation; & to solve for "x" ; 

→ -8x / -8 = -104/-8 ; 

→  x = 13
__________________________________________________________
Now, to find the value of "B" :
__________________________________________________________
  "B = - 6x + 169 " ;  ↔  B = 169 − 6x ;  

↔  B = 169 − 6x ;  

         = 169 − 6(13) ;   ===========> Plug in our "solved value, "13",  for "x" ;

         = 169 − (78) ; 

         = 91 ;

   B   = " 91 " .
__________________________________________________
The answer is:  " 91 " . 
____________________________________________________
     →     " B = 91 " . 
____________________________________________________
Now;  let us check our answer:
____________________________________________________
               →   A + B = 180 ;  
____________________________________________________
Plug in our "solved answer" ; which is "91", for "B" ;  as follows:
________________________________________________________

→  A + 91 = ? 180? ;  

↔  A = ? 180 − 91 ? ; 

→  A = ?  -89 ?  Yes!
________________________________________________________
→  " A =  -2x + 115 " ;   ↔  A =  115 − 2x ;  

Plug in our solved value for "x"; which is: "13" ; 

" A = 115 − 2x " ; 

→  A = ? 115 − 2(13) ? ;

→  A = ? 115 − (26) ? ; 

→  A = ? 29 ? Yes!
_________________________________________________ 
METHOD 2)
_________________________________________________
Given:  
__________________________________________________
    "  A +  B = 180 " ;

  "A =  -2x + 115 " ;   ↔  A =  115 − 2x ;  

  "B = - 6x + 169 " ;  ↔  B = 169 − 6x ; 

→  Solve for the value of "B" :
_______________________________________________________
 A + B = 180 ;  

→ B = 180 − A ; 

→ B = 180 − (115 − 2x) ; 

→ B = 180 − 1(115 − 2x) ;  ==========> {Note the "implied value of "1" } ; 
__________________________________________________________
Note the "distributive property" of multiplication:__________________________________________________  a(b + c)  = ab +  ac ;  <u><em>AND</em></u>:
  a(b − c)  = ab − ac .________________________________________________________
Let us examine the following part of the problem:
________________________________________________________
              →      " − 1(115 − 2x)  " ; 
________________________________________________________

→  "  − 1(115 − 2x) " = (-1 * 115) − (-1 * 2x) ;

                                =  -115 − (-2x) ;
                         
                                =  -115  +  2x ;        
________________________________________________________
So we can bring down the:  " {"B = 180 " ...}"  portion ; 

→and rewrite:
_____________________________________________________

→  B = 180 − 115 + 2x ; 

→  B = 65 + 2x ; 
_____________________________________________________
Now;  given:   "B = - 6x + 169 " ;  ↔  B = 169 − 6x ; 

→ " B =  169 − 6x  =  65 + 2x " ; 
______________________________________________________
→  " 169 − 6x  =  65 + 2x "

Subtract "65" from each side of the equation;  & Subtract "2x" from each side of the equation:

→  169 − 6x − 65 − 2x  =  65 + 2x − 65 − 2x ; 

to get:

→   " - 8x + 104 = 0 " ;
 
Subtract "104" from each side of the equation:

→   " - 8x + 104 − 104 = 0 − 104 " ;

to get: 

→   " - 8x = - 104 ;

Divide each side of the equation by "-8" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  -8x / -8  = -104 / -8 ; 

to get:

→  x =  13 ; 
______________________________________________________

Now, let us solve for:  " B " ;  → {for which this very question/problem asks!} ; 

→  B = 65 + 2x ;  

Plug in our solved value, " 13 ",  for "x" ; 

→ B = 65 + 2(13) ; 

        = 65 + (26) ;  

→ B =  " 91 " .
_______________________________________________________
Also, check our answer:
_______________________________________________________
Given:  "B = - 6x + 169 " ;   ↔  B = 169 − 6x = 91 ; 

When "x  = 13 " ; does: " B = 91 " ? 

→ Plug in our "solved value" of " 13 " for "x" ;

      → to see if:  "B = 91" ; (when "x = 13") ;

→  B = 169 − 6x ; 

         = 169 − 6(13) ; 

         = 169 − (78)______________________________________________________
→ B = " 91 " . 
______________________________________________________
6 0
2 years ago
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