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3 years ago

Which golfer is the least consistent

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

8 0

The least consistent would be A i think, not for sure

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As a sales analyst for the shoe retailer Foot Locker, one of your responsibilities is measuring store productivity and then repo

yKpoI14uk [10]

Answer:

the answer is going to be $350

Step-by-step explanation:

7 0

3 years ago

Need help with this geometry assignment due soon smart people and mark Brainly

skad [1K]

Answer:

1. a + b + c = 180

2. b + d = 180

3. d = a + c

Step-by-step explanation:

1. a + b + c = 180:

Angles in a triangle add up to 180

2. b + d = 180:

Angles in a straight line equal 180 because they are supplementary angles

3. d = a + c:

ΔACD is an exterior angle, and ΔACB is interior adjacent, hence ∠a and ∠c add up to ∠d

3 0

3 years ago

Read 2 more answers

Question 1

777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

$n = 6 + 4p$

In which p is the current position.

How many tiles would there be in position 22?

This is n when $p = 22$ . So

$n = 6 + 4*22 = 6 + 88 = 94$

There would be 94 tiles.

8 0

3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

On a piece of paper, graph y+2>-3x - 3. Then determine which answer

zmey [24]

Answer:

Step-by-step explanation:

【Look at the image】

7 0

3 years ago

Read 2 more answers