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3 years ago

Plzzz help me this is for a exam!

Mathematics

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:

part A: f(n) = 10(1.02)^n

f'(n) = 10n (1.02)^n-1

Part B and C no idea

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I need some help with this

masya89 [10]

Answer:

A, C, D

Step-by-step explanation:

Consider triangles NKL and NML. These triangles are right triangles, because

$m\angle K=m\angle M=90^{\circ}$

In these right triangles:

$\overline{NL}\cong \overline {NL}$ - reflexive property;
$\angle KLN\cong \angle MLN$ - given

Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so

$\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]$

Since

$\overline{KN}\cong \overline{NM},$

then

$7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]$

Option B is false, because KN=52 units.

Option E is false, because LN is congruent KN, not LM

4 0

3 years ago

Write an expression for "10 multiplied by u

raketka [301]

An expression for that would be 10u

6 0

3 years ago

Read 2 more answers

The distance D (in miles) a car travels is related to how last, the rate R. the car is going and the amount of time T (in hours)

Alika [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

The graph of the equation x^2+6x+y^2-16y=-9 is a circle. Choose True or False for each statement

BigorU [14]

Answer:

see the explanation

Step-by-step explanation:

we have

$x^2+6x+y^2-16y=-9$

Convert the equation of the circle in center radius form

Group terms that contain the same variable

$(x^2+6x)+(y^2-16y)=-9$

Complete the square twice. Remember to balance the equation by adding the same constants to each side

$(x^2+6x+9)+(y^2-16y+64)=-9+9+64$

$(x^2+6x+9)+(y^2-16y+64)=64$

Rewrite as perfect squares

$(x+3)^2+(y-8)^2=8^2$

The center of the circle is (-3,8)

The radius of the circle is 8 units

Verify each statement

A. The center of the circle is (3,-8).

False

The center of the circle is (-3,8)

B. The circle is tangent to the x-axis

True

The circle is tangent to x=5 and x=-11 and is tangent to y=0 and y=16

Remember that y=0 is the x-axis

C. The circle has a radius of 64

False

The radius of the circle is 8 units

7 0

3 years ago

How do you know where and when the graph crosses the horizontal asymptote?

Genrish500 [490]

The horizontal asymptote is the line which the curve approaches to cross but never crosses the boundary. The horizontal asymptote can be identified when the exponent in the denominator of the function is larger than the exponent in the numerator. If not, no horizontal asymptote exists. WHen there is, we equate the denominator to zero and get x

7 0

3 years ago