In AABC, the measure of ZC=90°, the measure of ZA=63°, and AB = 35 feet. Find the

19.27 - (- 42.1)= subtract

Damm [24]

Answer:

61.37

Step-by-step explanation:

when you subtract twice you are essentially adding

so

19.27 + 42.1 is that you are doing

and that is

61.37

8 0

2 years ago

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A number cube is rolled 240 times. Six comes up 41 times. What is the theoretical probability of rolling a six

Rainbow [258]

Since Theoretical probability is the ratio desired outcomes/total outcomes, the theoretical probability would be 41/240

3 0

3 years ago

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A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price

Nataliya [291]

Answer:

a) $P=3(120-s)+200$

b) $215 \leq P \leq 290$

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

$s$ number of seats, if w analyze the info given the number of seats after increase the price is given by $120-s$ .

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

$P-200=3(120-s)$

So then our linear equation is given by:

$P=3(120-s)+200$

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

$P_L=3(120-90)+200=290$

$P_U=3(120-115)+200=215$

So the corresponding range of ticket prices is:

$215 \leq P \leq 290$

4 0

2 years ago

If A = (0, 0) and B = (6, 3) what is the length of overline AB ?

Kaylis [27]

Answer:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

$d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}$

And replacing we got:

$d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}$

So then the length AB would be $3\sqrt{5}$

Step-by-step explanation:

For this case we have the following two points:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

$d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}$

And replacing we got:

$d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}$

So then the length AB would be $3\sqrt{5}$

7 0

3 years ago

Help meeeee doooo thissss

lesya692 [45]

Answer:

B: x=-5 and x=4

Step-by-step explanation:

f(x)= x^2 + x -20

To find the zeros we replace f(x) with 0

$0= x^2 + x -20$

now we solve for x

LEts factor x^2 + x -20

sum is +1 and product is -20

5 * (-4)= -20

5 + (-4) = +1

x^2 + 5x - 4x - 20 = 0

(x^2 + 5x)+(- 4x - 20) = 0

x(x+5) -4 (x+5) = 0

(x-4)(x+5)=0

Set each factor =0 and solve for x

x- 4 =0 so x=4

x+5 =0 so x=-5

x=-5 and x=4

3 0

3 years ago