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lord [1]
2 years ago
14

What is the max or min and range of y=2x^2+20x-12

Mathematics
1 answer:
shtirl [24]2 years ago
4 0

Answer: its x = 3

Step-by-step explanation:

The maximum or minimum of a quadratic function occurs at

x

=

−

b

2

a

. If

a

is negative, the maximum value of the function is

f

(

−

b

2

a

)

. If

a

is positive, the minimum value of the function is

f

(

−

b

2

a

)

.

f

min

x

=

a

x

2

+

b

x

+

c

occurs at

x

=

−

b

2

a

Find the value of

x

equal to

−

b

2

a

.

x

=

−

b

2

a

Substitute in the values of

a

and

b

.

x

=

−

−

12

2

(

2

)

Remove parentheses.

x

=

−

−

12

2

(

2

)

Simplify

−

−

12

2

(

2

)

.

Tap for more steps...

x

=

3

The maximum or minimum of a quadratic function occurs at

x

=

−

b

2

a

. If

a

is negative, the maximum value of the function is

f

(

−

b

2

a

)

. If

a

is positive, the minimum value of the function is

f

(

−

b

2

a

)

.

f

min

x

=

a

x

2

+

b

x

+

c

occurs at

x

=

−

b

2

a

Find the value of

x

equal to

−

b

2

a

.

x

=

−

b

2

a

Substitute in the values of

a

and

b

.

x

=

−

−

12

2

(

2

)

Remove parentheses.

x

=

−

−

12

2

(

2

)

Simplify

−

−

12

2

(

2

)

.

Tap for more steps...

x

=

3

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