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lord [1]
2 years ago
14

What is the max or min and range of y=2x^2+20x-12

Mathematics
1 answer:
shtirl [24]2 years ago
4 0

Answer: its x = 3

Step-by-step explanation:

The maximum or minimum of a quadratic function occurs at

x

=

−

b

2

a

. If

a

is negative, the maximum value of the function is

f

(

−

b

2

a

)

. If

a

is positive, the minimum value of the function is

f

(

−

b

2

a

)

.

f

min

x

=

a

x

2

+

b

x

+

c

occurs at

x

=

−

b

2

a

Find the value of

x

equal to

−

b

2

a

.

x

=

−

b

2

a

Substitute in the values of

a

and

b

.

x

=

−

−

12

2

(

2

)

Remove parentheses.

x

=

−

−

12

2

(

2

)

Simplify

−

−

12

2

(

2

)

.

Tap for more steps...

x

=

3

The maximum or minimum of a quadratic function occurs at

x

=

−

b

2

a

. If

a

is negative, the maximum value of the function is

f

(

−

b

2

a

)

. If

a

is positive, the minimum value of the function is

f

(

−

b

2

a

)

.

f

min

x

=

a

x

2

+

b

x

+

c

occurs at

x

=

−

b

2

a

Find the value of

x

equal to

−

b

2

a

.

x

=

−

b

2

a

Substitute in the values of

a

and

b

.

x

=

−

−

12

2

(

2

)

Remove parentheses.

x

=

−

−

12

2

(

2

)

Simplify

−

−

12

2

(

2

)

.

Tap for more steps...

x

=

3

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Artist 52 [7]

Answer:

The statement is always TRUE

Step-by-step explanation:

An equilateral triangle has all angles and all sides equal

The sum of angles in a triangle is 180 degrees.

Let each of the angles be x degrees.

Then we solve the following equation for x.

x+x+x=180\degree

\implies 3x=180

\implies x=\frac{180}{3}=60\degree

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Someone please help me. Thanks!
fiasKO [112]
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Step-by-step explaination
6 0
3 years ago
1. find the equation of the circle with center at (-3,1) and through the point (2,13)
daser333 [38]
Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
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the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
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