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seropon [69]
3 years ago
10

If Debbie starts a retirement account with 10,000 dollars that has an annual rate of return of 12%, how long (in years) would it

take for her to have at least 100,000 dollars if interest is compounded continuously?
Mathematics
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

19.2 years

Step-by-step explanation:

The formula to find the time in a compound interest that is compounded continuously is given as:

t = ln(A/P) / r

Where:

t = time in years = ??

A = Amount after Interest is compounded continuously = $100,000

P = Initial Amount in the retirement account = $10,000

r = Rate of return = 12%

First, convert R percent to r a decimal

r = R/100

r = 12%/100

r = 0.12 per year,

Then, solve our equation for t

t = ln(A/P) / r

t = ln(100,000.00/10,000.00) / 0.12

t = 19.188 years

Approximately t = 19.2 years

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In a study to compare two different corrosion inhibitors, specimens of stainless steel were immersed for four hours in a solutio
djverab [1.8K]

Answer:

(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862

(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138

And the 95% confidence interval for the difference in the means is given by: 10.862 \leq \mu_A -\mu_B \leq 33.138

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_A = 242 sample mean for inhibitor A

s_A = 20 sample standard deviation for inhibitor A

n_A = 47 sample size for A

\bar X_B = 220 sample mean for inhibitor B

s_B = 31 sample standard deviation for inhibitor B

n_B = 42 sample size for A

Solution to the problem

For this case the confidence interval for the difference of means is given by:

(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_A}{n_A} +\frac{s^2_B}{n_B}}

The degrees of freedom are given by:

df = n_A +n_B -2 = 47+42-2= 87

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,87)".And we see that t_{\alpha/2}=1.988

And replacing we got:

(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862

(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138

And the 95% confidence interval for the difference in the means is given by: 10.862 \leq \mu_A -\mu_B \leq 33.138

4 0
3 years ago
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kykrilka [37]

Answer:

P = 10x + 4

Step-by-step explanation:

Formula to find perimeter:

P = 2(l + w)

P = 2(2x + 3x + 2)

P = 2(5x + 2)

P = 10x + 4

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baherus [9]

Answer:

parallel to the base

Step-by-step explanation:

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Answer:

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6 0
4 years ago
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