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SVETLANKA909090 [29]

3 years ago

12

(2h3 + 6h) + (3h3 - 7h - 3) standard form sum or difference.

1 answer:

worty [1.4K]3 years ago

3 0

Answer:

$5h^3- h - 3$

Step-by-step explanation:

Given

$(2h^3 + 6h) + (3h^3 - 7h - 3)$

Required

Standard form

We have:

$(2h^3 + 6h) + (3h^3 - 7h - 3)$

Remove bracket

$(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 6h + 3h^3 - 7h - 3$

Collect like terms

$(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 3h^3+ 6h - 7h - 3$

$(2h^3 + 6h) + (3h^3 - 7h - 3) = 5h^3- h - 3$

Hence, the standard form is:

$5h^3- h - 3$

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Suppose the radius of a circle is 8. What is its area?

monitta

The Formula to find the Area of a circle using the radius is:
$A = \pi r^2$

r = 8
So:
$A = \pi r^2$
$A = \pi 8^2$
$A = \pi64$

And you get about 201.06193

So, the area of a circle with a radius of 8 is about 201.06

Hope this Helps :)

3 0

3 years ago

Greatest to least 0.04; 0.5; 0.021; 0.133

babymother [125]

0.5, 0.04, 0.133, 0.021

4 0

3 years ago

Read 2 more answers

PLEASE HELP (100 POINTS)

omeli [17]

$\\ \rm\Rrightarrow 2sin^2x=1-cosx$

$\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x$

$\\ \rm\Rrightarrow 2sin^2x-sin^2x=0$

$\\ \rm\Rrightarrow sin^2x=0$

$\\ \rm\Rrightarrow sinx=0$

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6 0

2 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

P(n)=2n^2-6n find p(4)

Igoryamba

let's solve for p(4) :

$2 {n}^{2} - 6n$

$2 \times (4) {}^{2} - (6 \times 4)$

$(2 \times 16) - 24$

$32 - 24$

$8$

4 0

3 years ago