If the ball has an initial velocity of 130 ft/s and an angle of 41°, the time it will take the ball to hit the ground is 5.33 seconds
Since the ball is a projectile, we need to find its time of flight for it to reach the ground
<h3>Time of flight of ball</h3>
The time of flight of the ball is the time it will take to hit the ground. It is given by
T = 2UsinФ/g where
- U = speed of ball = 130 ft/s
- Ф = angle of projection = 41° and
- g = acceleration due to garvity = 32 ft/s²
Substituting the values of the variables into the equation, we have
T = 2UsinФ/g
T = 2 × 130 ft/s × sin41° ÷ 32 ft/s²
T = 260 ft/s × 0.6561 ÷ 32 ft/s²
T = 170.58 ft/s ÷ 32 ft/s²
T = 5.33 seconds
So, the time it will take the ball to hit the ground is 5.33 seconds
Learn more about time of flight here:
brainly.com/question/24136952
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If the second beacon is 120° after the first, then the first is 360° -120° = 240° after the second. The ratio of the times between beacons is
120° : 240° = 1 : 2
The appropriate choice is
E. 1:2
hi <3
84 + 4m = 276
subtract 84 from both sides:
4m = 192
divide both sides by 4:
m = 192/4 = 48
hope this helps :)
Your answer would be c<em>= b- d/a</em>
Answer:
(f + g)(x) = – 3x^2 + 5x - 8
Step-by-step explanation:
(f + g)(x) = f(x) + g(x)
= 5x^2 + 9x – 4 + (– 8x^2 – 3x – 4)
= 5x^2 + 9x – 4 – 8x^2 – 3x – 4
Combine
= – 3x^2 + 5x - 8
