45 because you do 210-120 which is 90. 90÷2 is 45.
-JZ
-2x - 4 = 12
add 4 to both sides of the equation
-2x = 16
divide -2 from both sides of the equation
x = -8
the new fraction: 8/3 or 2 2/3
Area of the square = (9 m)^2 = 81 m^2
The four circular sectors combine to form a circle with diameter 9 m, hence radius 4.5 m.
Area of the circle = π (4.5 m)^2 = 20.25π m^2
Then the area of the shaded region is
81 m^2 - 20.25π m^2 ≈ 17.4 m^2
Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
