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Rzqust [24]
3 years ago
9

SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

a) C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty).

b) C(x) decreases in (8\,s, 10\,s).

Step-by-step explanation:

Let C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850, where x is the quantity of insecticide, measured in hundreds of liters, and C(x) is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of C(x) are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

C'(x) = 3\cdot x^{2}-54\cdot x+240 (1)

Please notice that regions where C(x) is increasing has C'(x) > 0, whereas C'(x) < 0 when C(x) < 0.

We notice that C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty). Besides, C(x) decreases in (8\,s, 10\,s).

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Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

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We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

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General form of quadratic equation is ax^2+bx+c

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On substituting the values in formula we get

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Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



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