Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!
For this problem you have yo set up two equations.
White shirts = w Yellow shirts = y
1st: w + y = 21
2nd: 9.95w + 11.50y = 235.30
Now we're going to do system of equations using substitution.
If w + y = 21, then y = 21 - w
If y = 21 - w, then you can substitute this in the second equation for y.
9.95w + 11.50(21 - w) = 235.30
9.95w + 241.5 - 11.50w = 235.30
-1.55w + 241.5 = 235.30
-1.55w = -6.2
w = 4, so 4 whites shirt were sold.
Now I'm finding out how many yellow shirts were sold using one of the two equations at the top.
w + y = 21
4 + y = 21
y = 17
So 17 yellow shirts were sold and 4 white shirts were sold.
Answer:
No solutions
Step-by-step explanation:
![2a+\dfrac{3}{2}-a-\dfrac{2}{3}=a-\dfrac{1}{4}\\a+\dfrac{5}{9}=a-\dfrac{1}{4}\\\dfrac{5}{9}=\dfrac{1}{4}](https://tex.z-dn.net/?f=2a%2B%5Cdfrac%7B3%7D%7B2%7D-a-%5Cdfrac%7B2%7D%7B3%7D%3Da-%5Cdfrac%7B1%7D%7B4%7D%5C%5Ca%2B%5Cdfrac%7B5%7D%7B9%7D%3Da-%5Cdfrac%7B1%7D%7B4%7D%5C%5C%5Cdfrac%7B5%7D%7B9%7D%3D%5Cdfrac%7B1%7D%7B4%7D)
This equation has no solutions. Hope this helps!
18 |16 | 13 | 10 | 9.5 | 8.5 | 7.5 | 6
9.75 is the FINAL answer