Alexa and Daniel , two students of middle school together collected $20 from the students for annual function of their school .
1 answer:
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Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Answer:
Rule: dilation about the origin by a scale factor of 2
Step-by-step explanation:
Given
See attachment for QRST and Q'R'S'T
Required
The dilation rule
First, we calculate the scale factor (k)
From the attachment, we have:
k, is then calculated as:
<em>Hence, QRST is dilated by a factor of 2</em>
