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torisob [31]
3 years ago
9

How would I solve this?

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

you have to find the value of k

Step-by-step explanation:

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If the volume of a cube is increased by a factor of 10 (so that the new volume is 10 times the size of the original volume), by
Alexeev081 [22]

Answer:

surface area of cube 10^{\frac{2}{3} } time

Step-by-step explanation:

given data

new volume =  10 time original volume

to find out

what factor surface area change

solution

we consider here side of cube is a

and volume is V

we consider here a is 2

then volume will be v1 = a³ = 2³ = 8

and surface area = 6a²    = 6(2)² = 24    ..........1

so if volume increase 10 time

than

V = 10 × v1

a³ = 10 × 8

a³= 80

a = 2 × ∛10

and

surface area increase here

surface area = 6a²

surface area = 6( 2 × ∛10 )²

surface area = 24 × 10^{\frac{2}{3} }    ............2

so from equation 1 and 2

surface area / surface area = 24 × 10^{\frac{2}{3} }  / 24

surface area = 10^{\frac{2}{3} }

so here surface area of cube will be 10^{\frac{2}{3} } time

5 0
4 years ago
(15/8+2/5)+(-7/8) show ur work
stepan [7]
The answer is 7/5 th. You can add fractions without first having a common denominator so you would change the 8's by multiplying it by 5 to get 40 and you would multiply the 5 by 8 to get 40 as well. And the rule whatever you do to the bottom you have to do to the top so whatever you multiplied 8 by do the same for the numerator and whatever you multiplied 5 by you do the same for the numerator. So your new equation would be (75/40+16/40)+(-35/40). you would then add the numerator's across to get 56 and the denominator would stay the same so the answer is 56/40. But you have to now simplify 56/40 down to 14/10 and then once more to 7/5 which is the final answer.
6 0
4 years ago
Consider an experiment in which a fair coin is tossed until a head is obtained for the first time. If this experiment is perform
pychu [463]

Answer:

P(A_1 = A_2 =A_3) = \frac{1}{1-\frac{1}{8}} -1 =\frac{1}{7}

Step-by-step explanation:

For this case we assume that the probability of obtain a head is 1/2

P(H) =\frac{1}{2}

We are conducting the experiment 3 times. And we want the probability that exactly the same number of tosses will be required for each of the 3 performances.

We can model the situation like this. Let A_i the number of tosses used in the performance, for this case A_i \geq 1

And the distribution for A_i would be a negative binomial with the following mass function:

P(A_i = r)= (1-\frac{1}{2})^{r-1} \frac{1}{2}= (\frac{1}{2})^r

Now we need to assume that the 3 performaces are independent from each other and we want this:

P(A_1 = A_2 =A_3) =\sum_{r=1} P(A_i = r)^3

And we can since we have the mass function we can replace:

P(A_1 = A_2 =A_3) =\sum_{r=1} (\frac{1}{2})^{3r}

P(A_1 = A_2 =A_3) = \sum_{r=1} (\frac{1}{8})^r

And as we can see we have a geamotric series and we can find the probability like this:

P(A_1 = A_2 =A_3) = \frac{1}{1-\frac{1}{8}} -1 =\frac{1}{7}

8 0
3 years ago
Stella invested $6,100 in an account paying an interest rate of 6 1/2%compounded
grandymaker [24]

Answer:

9662.3822

Step-by-step explanation:

4 0
3 years ago
Help PLZZ no files PLZZ NO FILES
laiz [17]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
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