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Marina CMI [18]
3 years ago
7

WILL GIVE BRAINLIEST PLEASE HELP WITHIN 15 MINUTES!!

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

60 & 42

Step-by-step explanation:

Just know it.

Good Luck!!

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17.45 how do you mixed numbers and reduce
Vadim26 [7]

<em>Hello!</em>

<em>17.45 as a mixed fraction is </em><em>17 9/20</em><em>.</em>

<em>If this is not correct, please comment below and I will try my best to find the right answer.</em>

5 0
3 years ago
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Which expression is equivalent to (2^3) ^5?<br> оооо
gregori [183]

Step-by-step explanation:

\text{Use}\ (a^n)^m=a^{nm}\\\\(2^3)^5=2^{3\cdot5}=2^{15}

6 0
3 years ago
Read 2 more answers
|3x-7| + 7 = 9 What is the first solution?<br><br> Plzzz help
posledela

Answer:

  • 3 and 5/3

Step-by-step explanation:

<u>Solving in steps:</u>

  • |3x-7| + 7 = 9
  • |3x-7|  = 2

<u>1. If 3x - 7 > 0</u>

  • 3x - 7 = 2
  • 3x = 9
  • x = 3

<u>2.  If 3x - 7 < 0</u>

  • 3x - 7 = -2
  • 3x = 5
  • x = 5/3
5 0
3 years ago
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a ne
Evgen [1.6K]

Answer:

a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between 0.6290 and 0.6948.

b. If the sample size is changed, the confidence interval changes as the standard error depends on sample size.

About 90% percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 10% percent will not contain the true population proportion.

Step-by-step explanation:

We have to calculate a 90% confidence interval for the proportion.

The sample proportion is p=0.6619.

p=X/n=370/559=0.6619

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.6619*0.3381}{559}}\\\\\\ \sigma_p=\sqrt{0.0004}=0.02

The critical z-value for a 90% confidence interval is z=1.6449.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.6449 \cdot 0.02=0.0329

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.6619-0.0329=0.6290\\\\UL=p+z \cdot \sigma_p = 0.6619+0.0329=0.6948

The 90% confidence interval for the population proportion is (0.6290, 0.6948).

3 0
3 years ago
Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi
algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

3 0
3 years ago
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