1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Because the coefficient of x^2 is -1, we know that a will be -1. Knowing that the coefficient of x is -4, we can calculate that p=2. Thus, we have -1(x+2)^2+q is our equation. This is equal to -x^2-4x-4+q. As the constant term must be 2, we can then see that q is 6.
As such, we have -1(x+2)^2+6=0 as our factorization.
To solve this equation, we can use the quadratic formula. Plugging in values, we have:

which is equal to: (when the fraction is simplified)
Answer:
You need to carry the one over by subtracting 1 from 33. The new equation will be 18n = 32
<span>In getting the value of R in the formula of the circumference that you give where as the circumference is equals to 15, the derived formula is R=C/2pi and the answer would be that R is equals to 2.39. I hope you are satisfied with my answer and feel free to ask for more if you have more questions and further clarifications </span>
I think the length of pool in inches is actually 12*12=144 because there are 12 inches in a foot.
Also, the scale factor would be 144/16 = 9.