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3 years ago

How to write this numbers in word 23.13

Mathematics

2 answers:

Gennadij [26K]3 years ago

5 0

Answer:

twenty three and 13 hundredths

MissTica3 years ago

5 0

Answer:

Twenty three point thirteen

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A student answered 86 problems on a test correctly and received a grade of 98%. How many problems were on the test, if all the p

balu736 [363]

Answer:

88 problems

Step-by-step explanation:

Set this problem up as fractions

86/x = 98/100

Cross multiply

86 × 100 = x × 98

8600 = 98x

Divide both sides by 98

87.75... = x

Round to nearest whole number

87.75 rounds up to 88

88 problems

7 0

3 years ago

Help im being timed

Oksanka [162]

Answer:

he made the error in step 2

Step-by-step explanation:

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3 years ago

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Draw a number line and mark all described points on it. Numbers that are both larger than –2 and smaller than 3.

vfiekz [6]

Answer:

The numbers larger than -2 and smaller than 3 are -1,0,1,2.

Step-by-step explanation:

4 0

4 years ago

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Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago

Which of the numbers below could be terms in the sequence an=7n +4?<br> 24<br> 46<br> 32<br> 36

mrs_skeptik [129]

Answer:

Step-by-step explanation:

46 - 4 = 42

42/7 = 6

7 0

3 years ago

How to write this numbers in word 23.13​

How to write this numbers in word 23.13