I think it's 0 since anything multiplied by 0 is, well, 0! No matter what the sign is. I believe the correct answer is 0 :)
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Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
Answer:
C. 1
Step-by-step explanation:
We can see that each box in the grid is one unit.
We count one box to the right on the horizontal axis and 4 boxes down on the vertical axes to obtain the components of vector v.
See graph in attachment.
Therefore the components of vector v is

.
The length of the x component is 1 unit
Hence the correct answer is C.
Answer:
35+8=43 ounnces
Step-by-step explanation:
The total cost for peaches is $0.40 you get that by (0.5)(0.80) as for oranges (0.7)(.90)=$0.63 so $0.40+$0.63=$1.03