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3 years ago

10

4.3(-3.2)0 positive or negative or zero Help

2 answers:

iragen [17]3 years ago

4 0

I think it's 0 since anything multiplied by 0 is, well, 0! No matter what the sign is. I believe the correct answer is 0 :)

S_A_V [24]3 years ago

3 0

Hi there! Anything times zero is always zero. There’s really nothing you need to do here, since the product is simply zero, no matter how you put it. In these kinds of problems, the answer is 0, and unless you have to add or subtract, the value remains at zero. The answer is zero.

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What is the difference between a line, line segment and a ray in geometry

bekas [8.4K]

a long, narrow mark or band.

line segment is a part of a line with two end points and all the points between tham.

a ray is a part of line made of 1 end points and all the points to 1 side.

5 0

3 years ago

I need help asap pls

Tema [17]

If Michael is bike riding at a speed of 4 miles an hour you would multiply 4 miles by the hour

So it would be x times y
0x4=0
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5 0

3 years ago

Read 2 more answers

I need help please QUIZ

krok68 [10]

Answer:

..so easy B

Step-by-step explanation:

its B

u put 2nd one in the formula.

8 0

2 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Hello :3 i'm giving out some points, I hope you have a nice day!

Allushta [10]

Answer:

12 x 12 = 144

Step-by-step explanation:

6 0

2 years ago