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fredd [130]
3 years ago
6

ac{x}{4} + \frac{2x}{4} " alt=" \frac{x}{4} + \frac{2x}{4} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0
3x/4 =3/4 x
That said
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Mila [183]

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3 years ago
What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to
yuradex [85]
Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius - 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m² = 6 m( 2 x radius - 6 m ) 
100 m² = 12 m x radius - 36 sq m 
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
<span>11.333 m = radius 
</span>
the area beneath an arc: 

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ). 
</span>
r² = (11.333 m)² = 128.444 m² 
r - h= 11.333 m - 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m 

Area = 138.828 m² - 53.333 m² 

Area = 85.4 m<span>²
</span>

Hope this Helps! Have A Wonderful Day! :)


And as Always...

7 0
3 years ago
Help please this is for inequality math!! n + 7 &lt; - 3
stealth61 [152]

Answer:

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Step-by-step explanation:

n+7 < -3

subtract 7 from both sides

n+7-7 < -3-7

n < -10

4 0
3 years ago
What is the slope of (2,-12), (18,15)
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

The slope of a line given two points (x_0,y_0) and (x_1,y_1) is

m=\frac{y_1-y_0}{x_1-x_0}=\frac{15-(-12)}{18-2}=\frac{27}{16}

7 0
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Triangle ABC has the following angle measurements
oksano4ka [1.4K]

Answer:

What kind of equation are we supposed to do here?

Step-by-step explanation:

If you tell me then I can help you.

5 0
3 years ago
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