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3 years ago

Rewrite the expression using the distributive property and collecting like terms

Mathematics

2 answers:

timofeeve [1]3 years ago

5 0

12x

The fractions cancel out, so it’s just 9x+3x

Bumek [7]3 years ago

3 0

12x would be the answer

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meriva

V={Vowels of English alphabets}

V={a,e,i,o,u,A,E,I,O,U}

C={cube numbers between 0 to 50}

C={0,1,8,27}

M={y:y is a multiple of 3 less than 20}

M={0,3,6,9,12,15,18}

6 0

2 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

Which ordered pair is a a solution of the equation ?

UNO [17]

Answer:

Step-by-step explanation:

when you plug in 2,11

11 = 3*2 +5 that is correct

13 = 3*3 +5 that is not correct

only 2,11 works

8 0

3 years ago

Read 2 more answers

A lumberjack can cut a log into 5 pieces in 20 minutes. How long does it take to cut a log of the same size and shape into 7 pie

Nitella [24]

Answer:

28minutes

Step-by-step explanation:

Use this simple trick, it can be used almost everywhere

Time taken pieces

20mins 5

? 7

An x shape is always multiply and straight line is divide

So (7 x 20) ÷5

If u still don't understand, just comment again

8 0

3 years ago

Pls pls help<br> Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

5 0

3 years ago