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Alexxandr [17]
2 years ago
9

Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard

deviation of a sample of that population? NO LINKS!!!
a. 99%
b. 80%
c. 95%
d. 90%​
Mathematics
2 answers:
Dvinal [7]2 years ago
4 0
<h3>Answer:  A) 99%</h3>

Explanation:

The larger the confidence level, the wider the confidence interval gets. Choice A provides the largest such confidence level.

It's like trying to catch an elusive fish. The wider the net, the more confident that you are likely to catch the fish. The size of the net can be a sort of measure of the confidence level.

White raven [17]2 years ago
4 0
  • Confidence level be x
  • Wideness of interval be y

The relation is

\\ \rm\Rrightarrow x\propto y

Higher the confidence level wider the interval.

So option A i.e 99% is correct

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In the diagram, ∠J ≅ ∠M and JL ≅ MR. What additional information is needed to show ΔJKL ≅ △MNR by SAS?
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Answer:

You will have to find out if JK ≅ MN

Step-by-step explanation:

SAS means you have 2 sides that are congruent that connect to make the one angle congruent.

Due to the fact that JL ≅ MR the sides that are left to make up the angles ∠J and ∠M

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In a certain​ lottery, an urn contains balls numbered 1 to 26. From this​ urn, 6 balls are chosen​ randomly, without replacement
expeople1 [14]

Answer:

\frac{1}{230230}

Step-by-step explanation:

Given that in a certain​ lottery, an urn contains balls numbered 1 to 26

From this​ urn, 6 balls are chosen​ randomly, without replacement.

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If these match with those chosen from the urn he wins (order does not matter)

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4 0
3 years ago
Do more than 50 percent of the children in a certain group have brown hair?
babymother [125]

Answer:

What we know is that 30% of the group have brown hair and are girls. It means that in the other 70% we have the boys with brown hair, the other boys and the other girls.

In the case all the girls have brown hair, the 70% remaining would be boys. So 70% of then would have brown hair. (0.7*0.7=0.49 -> 49% of the children would be brown hair) so 49% (boys) and 30% (girls) are more than 50%..

Now, let's suppouse that 90% of the group are girls. It means 10% are boys and 70% of that 10% (=7%) are the boys in the group that have brown hair. Now 7% + 30% of the children have brown hair, wich isn't more than the half.

We have explained with two extreme cases that the information is not enough for making a precise answer

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