All categories

3 years ago

!!!!!!! NEED HELP PLZZZ!!!!!!!!

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

6 0

Answer:

the second answer choice

Step-by-step explanation:

the first number shouldn't repeat in each equation

hope it helps! :)

lara31 [8.8K]3 years ago

5 0

Answer:

{(5,6), (6,5), (4,3), (9,0)}

Step-by-step explanation:

The answer is {(5,6), (6,5), (4,3), (9,0)} because there are no repeating x values.

For it to be a function there can't be more than one of the same x values (input).

Hope this helps

You might be interested in

Rewrite the product as a power: 0.027m^3

Alinara [238K]

(0.3m )³

note that 0.3 × 0.3 × 0.3 = 0.027, hence

0.027m³ = (0.03m)³

3 0

4 years ago

Read 2 more answers

What is the interquartile range of this data 0, 5, 10, 15, 20,

pentagon [3]

Answer:

Step-by-step explanation:

The range from Q1 to Q3 is the interquartile range (IQR).

The interquartile range is the difference between the third and first quartiles.

The third quartile is 17.5.

The first quartile is 2.5.

The interquartile range = <u>17.5 - 2.5</u> = 15.

6 0

3 years ago

Carmen has taken out a loan for $800 to buy a car. she plans to pay back the loan at a rate of $40 per month. ramona has borrowe

Bingel [31]

Answer:a

Step-by-step explanation: 20 x 25=500

3 0

2 years ago

Read 2 more answers

If R is between A and D and<br> DR = 8 and DA = 15 then AR=

dolphi86 [110]

Answer:

Step-by-step explanation:

heres a model

A ----------R---------D

A ----?-----R----8---D

A----------15----------D

15 - 8 = 7

AR = 7

5 0

3 years ago

MAJOR HELP!

ladessa [460]

Answer: Option A

$\theta=tan^{-1}(\frac{8}{6})$

Step-by-step explanation:

We can model the situation by means of a right triangle.

Where the angle $\theta$ is the angle that you make with the top of the TV.

Then the horizontal distance of 6 feet is the adjacent side and the vertical distance of 8 feet is the opposite side to the angle the.

By definition of the $tan(\theta)$ function we know that:

$tan(\theta)=\frac{opposite}{adjacent}$

Therefore:

$tan^{-1}(\frac{8}{6})=\theta$

$\theta=tan^{-1}(\frac{8}{6})$

6 0

3 years ago