Question

How many pounds of candy that cells for $0.66 per Ib must be mixed with candy that sells for $1.31 per Ib to obtain 9 Ib of a mixture that should sell for $0.97 per Ib?

Answer 1

Answer:  $\frac{306}{65}$ pounds

Step-by-step explanation:

Let x pounds of $ 0.66 per lb candies mixed with y pounds of $ 1.31 per lb candies to obtain 9 lb of $ 0.97 per lb candies,

Hence, we can write,

x + y = 9 ------- (1)

And, 0.66 of x + 1.31 of y = 0.97 of (x + y)

⇒ 66 x + 131 y = 97 (x+y)

⇒ 66 x +131 y - 97 x - 97 y = 0

⇒ -31 x + 34 y = 0  ------(2)

By solving equation (1) and (2)

We get,

$x=\frac{306}{65}$ and $y=\frac{279}{65}$

Hence, the quantity of 0.66 per lb candies = $\frac{306}{65}$  pounds