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3 years ago

Need help please I'm not sure if I'm right

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

The angles inside a triangle always sum to 180°. We already have a 32° angle and a 90° - totalling 122° - and when we add x°, we'd like the sum to be 180°. So x must be 180 - 122 = 58.

Vlad1618 [11]3 years ago

5 0

Answer:

Step-by-step explanation:

The total should be 180 degrees. We know the the top angle is 32 degrees and the bottom left is 90 degrees because it has a square there. So 32+90=122. If we subtract 122 from 180 we are left with 58 degrees so x=58

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What is the answer of. 4y+7>-x-3

lora16 [44]

I don’t know what u need to look for but I think for y
4y+7>-x-3
4y>-x-10
y>-1/4x-5/2

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3 years ago

If a jar of peanut butter cost $4.69 how much would it cost to buy $36

Deffense [45]

For 36 dollars, you would get 7 jars. This is b/c 36 dollars divided by $4.69, is 7
To buy 36 jars you would need $168.84 This is b/c 36 times $4.69 is $168.84
Hope that helped

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4 years ago

carla andrade has $215.25 deducted from her semimonthly pay for group health insurance rocky mountain auto parts her employer pa

Olegator [25]

Answer:

its 86.06

Step-by-step explanation:

Because if you subtract 215.25 minus 60% thats what you get

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2 years ago

My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits. Write the 2-digit number that match

pochemuha

Answer:

The number is 91

Step-by-step explanation:

Let x be the ones place digit and y be the tens place digit,

Then the number would be 10y + x,

We have,

y - x = 8

Possible values of y and x = { (8, 0), (9, 1) }

∵ 0 is not the digit of the number,

Hence, y = 9 and x = 1

Therefore, required number = 10(9) + 1 = 90 + 1 = 91

6 0

3 years ago

Read 2 more answers

Given the conditional statement ~p -> q which statement is logically equivalent?

icang [17]

Any implication is logically equivalent to its contrapositive. In other words,

¬p ⇒ q ⇔ ¬q ⇒ p

(¬ means the same thing as ~, "not")

To prove this: recall that

p ⇒ q ⇔ ¬p ∨ q

This is because p ⇒ q is true if p is false, or both p and q are true, i.e.

p ⇒ q ⇔ ¬p ∨ (p ∧ q)

Disjunction (∨ or "or") distributes over conjunction (∧ or "and"), so that

p ⇒ q ⇔ (¬p ∨ p) ∧ (¬p ∨ q)

but ¬p ∨ p is always true, or a tautology, so we're just left with ¬p ∨ q.

Then

¬p ⇒ q ⇔ p ∨ q

… ⇔ q ∨ p

… ⇔ ¬(¬q) ∨ p

… ⇔ ¬q ⇒ p

4 0

3 years ago

Need help please I'm not sure if I'm right​

Need help please I'm not sure if I'm right