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Anastasy [175]
2 years ago
13

Help need answers asap

Mathematics
1 answer:
Rasek [7]2 years ago
7 0

Answer:

x = 25

y = 6

Step-by-step explanation:

< B = < M

2x - 20 = 30

2x = 50

<u>x = 25</u>

AB = LM

7y - 8 = 2y + 22

5y = 30

<u>y = 6</u>

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3 years ago
Nanda Yueh and Lane Zuriff sell homes for ERA Realty. Over the past 6 months they sold 136 homes. Nanda sold 3 times as many hom
Marta_Voda [28]

Answer:

Lane sold 34 homes.

Nanda sold 102 homes.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

Nanda sold x homes

Lane sold y homes

Over the past 6 months they sold 136 homes.

This means that x + y = 136

Nanda sold 3 times as many homes as Lane.

This means that x = 3y

Replacing in the first equation:

x + y = 136

3y + y = 136

4y = 136

y = \frac{136}{4} = 34

Lane sold 34 homes.

x = 3y = 34*3 = 102

Nanda sold 102 homes.

5 0
3 years ago
How do you solve 3y=6x-5?
jeka94

Answer:

Hope this helps

Step-by-step explanation:


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3 years ago
The diagram shows circle C. Which of these statement is true?
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3 years ago
(Geometry course question) Explain why it is not possible to construct an equilateral triangle that has
Nutka1998 [239]

Answer:

  √3 is irrational

Step-by-step explanation:

The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.

<h3 /><h3>Location of point C</h3>

With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)

<h3>Equilateral triangle</h3>

The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.

The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...

  \left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]

Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...

  cos(60°)·x + sin(60°)·y

will be irrational.

As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.

6 0
2 years ago
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