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Julli [10]
3 years ago
9

Does anyone know how to find mTDB?

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

nope

Step-by-step explanation:

nope

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A game is packaged in a box. Each game cube has a side length of 2 inches. How many games can be
gtnhenbr [62]

Answer:

432

Step-by-step explanation:

12/2 =6

24/2 = 12

12 * 6 * 6 is your answer.

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Find the area of the figure to the nearest tenth.
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Area is length x width
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Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
Read 2 more answers
1.5 x 32
Bingel [31]
1.5 x 32 = 48 12 divided 0.03 = 400 12.8 X 3/4 ( 0.75 ) =  <span>17.0666667 1.5 x 0.32 = 0 .48 1.2 divided by 0.3 = 4 AND... 102.4 divided 3.2 = 32 Hope this helps! :)
  </span>
5 0
3 years ago
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