Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and

Question

2 years ago

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Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and

the price of the sugar increased by 20% and the same quantity of tea and sugar cost rupees 48.30. Find their prices in January

Mathematics

2 answers:

aivan3 [116] · Answer 1 · 2022-08-12T21:01:06+03:00

Answer:

x = 15 rupees by kg ( price of tea)

y = 3 rupees by kg ( price of sugar)

Step-by-step explanation:

Let call " x " the price of kg of tea and " y " the price of kg of sugar, in january of 1997,

then according to problem statement

2*x + 3*y = 39 (1)

But in march prices increased

tea by 25% that means its price in march will be 1.25*x, and the price of sugar will be 1.20*y, finally buying the same quantities now cost 48.30 rupees, then

2* ( 1.25*x ) + 3 * ( 1.20*y) = 48.30

2,50*x + 3.60*y = 48.30 (2)

Equations (1) and (2) are a two equation system, we need to solve for x and y

From equation (1) we have y = ( 39 - 2*x ) / 3

Plugging that value in equation (2)

2,50*x + 3.60* [ ( 39 - 2*x ) / 3] = 48.30

2,50*x + ( 140,40 - 7,20*x ) /3 = 48.30

7.50*x + 140,40 - 7,20*x = 144,90

0,30*x = 4.50

x = 4.50/0.30

x = 15 rupees

and y = ( 39 - 2*x ) / 3 ⇒ y = ( 39 - 2*15 ) / 3

y = ( 39 - 30 )/3

y = 3 rupees

Irina18 [472] · Answer 2 · 2022-08-12T18:41:51+03:00

Answer: tea = 15 rupees per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":

2 t + 3 s =39 (a)

Where:

t= price of 1 kg of tea
s = price of 1 kg of sugar

"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "

2(t1.25)+3(s1.2) = 48.30 (b)