Question

Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and the price of the sugar increased by 20% and the same quantity of tea and sugar cost rupees 48.30. Find their prices in January

Answer 1

Answer:

x  =  15 rupees by kg   ( price of tea)

y  =  3 rupees by kg   ( price of sugar)

Step-by-step explanation:

Let call " x " the price of kg of tea and " y " the price of kg of sugar,  in january of 1997,

then according to problem statement

2*x + 3*y  =  39    (1)

But in march prices increased  

tea by 25%  that means its price in march will be 1.25*x, and the price of sugar will be 1.20*y, finally buying the same quantities now cost 48.30 rupees, then

2* ( 1.25*x )  +  3 * ( 1.20*y) = 48.30  

2,50*x  +  3.60*y  = 48.30     (2)

Equations (1) and (2) are a two equation system, we need to solve for x and y

From equation  (1)  we have    y = ( 39 - 2*x ) / 3

Plugging that value in equation (2)

2,50*x  + 3.60* [ ( 39 - 2*x ) / 3]   =  48.30

2,50*x  + ( 140,40 - 7,20*x ) /3   = 48.30

7.50*x  + 140,40  - 7,20*x  =  144,90

0,30*x  =  4.50

x =  4.50/0.30

x =  15  rupees

and  y  =   ( 39 - 2*x ) / 3     ⇒  y  = ( 39 - 2*15 ) / 3

y  = ( 39 - 30 )/3

y  =  3 rupees

Answer 2

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":

2 t + 3 s =39 (a)

Where:

• t= price of 1 kg of tea
• s = price of 1 kg of sugar

"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "

2(t1.25)+3(s1.2) = 48.30 (b)

• Solving for t in (b)

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

• Replacing the value of t in (b)

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

• Replacing the value of s in (a)

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.