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melomori [17]
3 years ago
13

2. If x1 is 3 and x2 is 2, how would you use the numbers in the slope formula?​

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0
M=y2-y1/2-3 j agree with the other person that just answered
torisob [31]3 years ago
3 0

Answer:

m = y2 - y1 / 2 - 3

Step-by-step explanation:

I believe it is asking you to plug in the numbers into the equation.

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Describe how to find the distance between two points on the coordinate plane.
zheka24 [161]

Answer: Dist = 8.94, midpoint = (1,6)

Step-by-step explanation:

Basically, the Distance between the points is the hypotenuse of a right triangle, whose legs are parallel to the x and y axes.

Leg 1 = x2 - x1 = 5 - -3 = 8

Leg 2 = y2 - y1 = 8-4 = 4

Hypotenuse = (8^2 + 4 ^2) ^ .5 = (64+16)^.5

Sqrt(80) = 8.94

The midpoint is aligned with the midpoint of each leg

X = 5 - 8/2 = 1

Y = 8 - 4/2 = 6

So (1,6) is the midpoint

5 0
3 years ago
What is the probability of getting a sandwich without muenster cheese?
vredina [299]

Answer:

Sorry, I need more information. What's the rest of the question?

3 0
3 years ago
What is the inverse of this function? (Function in photo)
valkas [14]

Given:

The function is

f(x)=-\dfrac{1}{2}\sqrt{x+3},x\geq -3

To find:

The inverse of the given function.

Solution:

We have,

f(x)=-\dfrac{1}{2}\sqrt{x+3}

Put f(x)=y.

y=-\dfrac{1}{2}\sqrt{x+3}

Interchange x and y.

x=-\dfrac{1}{2}\sqrt{y+3}

Isolate the variable y.

-2x=\sqrt{y+3}

(-2x)^2=y+3

4x^2-3=y

y=4x^2-3

Putting y=f^{-1}(x), we get

f^{-1}(x)=4x^2-3

For x\geq -3,

x+3\geq 0

\sqrt{x+3}\geq 0

-\dfrac{1}{2}\sqrt{x+3}\leq 0

f(x)\leq 0

It means for function f(x)\leq 0 and for inverse function x\leq 0 because the range of the function is the domain of inverse function.

Therefore, f^{-1}(x)=4x^2-3 for x\leq 0.

3 0
3 years ago
Help with the answer
svetlana [45]
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8 0
4 years ago
Read 2 more answers
What is the slope between the points?
Natali5045456 [20]

Answer:

C

Step-by-step explanation:

5 0
3 years ago
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