All categories

3 years ago

Find the image of (2,-7) after a reflection over the x-axis

Mathematics

1 answer:

asambeis [7]3 years ago

3 0

Answer: (2, 7)

Step-by-step explanation:

To reflect something over the x-axis, simply invert the y value. Simply turn -7 into 7.

Hope it helps <3 :)

You might be interested in

AB = 44 + 3xBC = 33 + yCD = 64 − xAD = 48 − 2yQuadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruen

Otrada [13]

The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.

Step-by-step explanation:

step 1 :

Given that,

Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

step 2 :

The opposite sides are AB and CD respectively.

The another opposite sides are BC and AD respectively.

step 3 :

If both pairs of opposite sides are congruent, then

AB = CD

44+3x = 64-x

3x+x = 64-44

4x = 20

x = 5

step 4 :

BC = AD

33+y = 48-2y

y+2y = 48-33

3y = 15

y = 5

step 5 :

Subsitute x=5 and y=5 in any of the given sides,

CD = 64-x = 64-5 = 59

∴ CD = 59 cm

BC = 33+y = 33+5 = 38

∴ BC = 38 cm

The lengths of the opposite side pairs are 59 cm , 38 cm.

3 0

3 years ago

Cindy earns $10.50 per hour working at a restaurant. On Friday, she spent 1 3/4 hours cleaning, 2 1/3 hours doing paperwork, and

AnnyKZ [126]

$61.25

All you have to do is add all the fractions and multiply it by 10.50

7 0

3 years ago

today only, a sofa is being sold at a 36% discount. The sale price is $560. what was the price yesterday?

pashok25 [27]

Answer:

Step-by-step explanation:

Let yesterday's price be x

Discount percentage = 36%

Sale price = $ 560

(100-36)% of x = 560

64 % *x = 560

$\frac{64}{100}*x=560\\\\x=560*\frac{100}{64}\\\\x=875$

Yesterday's price = $ 875

8 0

3 years ago

What is the volume of the cone?

mr_godi [17]

1/3 (3.14) (2*2) (4)

8 0

3 years ago

Help Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0

2 years ago