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2 years ago

Graph the solution set to the inequality.

Mathematics

2 answers:

zloy xaker [14]2 years ago

6 0

The person above me is right

denpristay [2]2 years ago

4 0

Answer:

The answer is the first one: s <= -18

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If the measure of arc XY plus the measure of a arc YZX equals 360 and the arcs dont overlapp then what do the arcs form?

gavmur [86]

Check the picture below.

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3 years ago

What is three-fourths of 1,968

lara31 [8.8K]

All you have to so is divide 1968 by 4.

1968 ÷ 4 = 496.5 = 1/4

Now multiply 496.5 by 3 = 1, 489.5 = 3/4

I hope this helps! :_

7 0

3 years ago

Read 2 more answers

Which theorem would be used to prove the triangles below as congruent?

Stells [14]

Answer:

A: HL

Step-by-step explanation:

The hypotenuses of these right triangles are marked congruent.

One leg of these right triangles is marked congruent.

The HL theorem applies.

4 0

2 years ago

Please help 4 math pages with questions. 1 has all the circle graphs, and all the other 3 have each circle graphs question. Plea

oksano4ka [1.4K]

Answer:

Favorite chip Answers v

Step-by-step explanation:

1. How many were surveyed? 82+8+18+62=100

2. How many said Jalepeno was their favorite? 8/100 0r 2/25 or 8%

3. How many said BBQ was their favorite?62/100 or 31/50 or 62%

4. How would it effect your final answer if the percentages did not add up to 100%? This means that your percentages are wrong. In a circle graph the percentages always equal 100%!

5. Is it possible to determine a missing percentage in a circle graph? Yes, we can always assume the total percentage is 100 so you add your given percentages together and then subtract that total from 100 to find the missing percentage.

8 0

1 year ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago