Seems to be an arythmetic sequence
Sn=[n(a1+an)]/2
where
Sn means sum of all terms up the nth term
n=number of terms
a1=first term
an=nth term
so from 86 to the 22th term is from a1 to a22
find teh sequence
miknus 7 each time
an=a1+d(n-1)
an=87-7(n-1)
find 22n term
a22=87-7(22-1)
a22=87-7(21)
a22=87-147
a22=-60
S22=[22(87-60)]/2
S22=[22(27)]/2
S22=594/2
S22=297
the sum is 297
Answer:
The first one is No. The second one I do not know unfortunately.
Step-by-step explanation:
I am in the middle of this lesson in my math class as well and I know that in order to make a triangle, you need the two smaller sides to add up to become larger than the biggest side. In the case of the first question, the two smaller sides, 6 and 3 equal 9, which is not bigger than the biggest side which is 10. I hope you can find the answer to the second one, but for now, the first one is No.
Answer:
-1.8, -2.1, -2.5, -2.7
Step-by-step explanation:
the bigger the negative number, the smaller it is
(f-g)(x) = f(x) - g(x) = 3^x + 10x - (4x - 2) = 3^x + 6x + 2 Answer
Answer:
f(1) = 4; f(n) = 4 + d(n - 1), n > 0.
Step-by-step explanation:
This arithmetic sequence has a common difference of d with first term = 4.
f(1) = 4; f(n) = 4 + d(n - 1), n > 0.
