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2 years ago

The variable y varies directly with x . If x=2 and y = −7, find y when x = −6.

Mathematics

2 answers:

telo118 [61]2 years ago

8 0

Step-by-step explanation:

$\frac{2}{ - 6} = \frac{ - 7}{y} \\ y = \frac{( - 6) \times (- 7)}{2} \\ y = \frac{42}{2} \\ \boxed{y = 21}$

<h2>21 is the right answer.</h2>

suter [353]2 years ago

7 0

Answer:

Step-by-step explanation:

X=2

Y=-7

Then if x is -6 u have to find what times 2 is -6 Which is -3.

so -7 x -3 is 21. Y is 21

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4. Given the points M(-3, -4) and T(5,0), find the coordinates of the point Q on directed line segment MT that partitions MT in

Firlakuza [10]

Answer:

<u><em>4 : </em></u> Coordinate of Q = $(\frac{1}{5} ,\frac{-12}{5} )$

<em><u>5 : </u></em> Coordinate of point A = (-2,-2)

Explanation :

4) Given the points M(-3, -4) and T(5,0)

x₁= -3, y₁ = -4 and

x₂ = 5, y₂ = 0

m = 2, n = 1

Now apply the section formula,

{(mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n)}

Coordinate of point Q = $(\frac{1}{5} ,\frac{-12}{5} )$

5) AB:BC = 3:4

A = (x,y), end point

B = (4, 1)

C = (12, 5) end point

So, m = 3 & n = 4

x₁ = x , y₁ = y , x₂=12 & y₂ = 5

Apply section formula we get

4 = (36+4x)/7 & 1 = (15 + 4y)/7

28= 36 + 4x 7 = 4y + 15

4x =-8 4y =-8

x = -2 y = -2

5 0

3 years ago

What is the value of the interquartile range of the data below?

Ahat [919]

The answer is 20 because if you subtract the two Q which is 40 and 20 that is your interquartile range

6 0

3 years ago

ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

3 years ago

Write in decimal form:

Nuetrik [128]

This makes no sense could you rewrite it please

6 0

2 years ago

Scientist A dissolved 1.0 kilogram of salt in 3.0 liters of water. Scientist B dissolved 2.0 pounds of salt into 7.0 pints of wa

solong [7]

The scientist that made a more concentrated salt solution is scientist A.

<h3>How to compute the value?</h3>

Since Scientist A dissolved 1.0 kilogram of salt in 3.0 liters of water. The concentration will be:

= 1/3 = 0.33

Scientist B dissolved 2.0 pounds of salt into 7.0 pints of water. The concentration will be:

= 2/7

= 0.285

Therefore, the scientist that made a more concentrated salt solution is scientist A.

Learn more about scientist on:

brainly.com/question/458058

#SPJ1

4 0

1 year ago